Average age of A and B is 50,000 days and average age of B and C is 60,000 days while average age of C and A is 55,000 days then calculate the age of B in days?
- 45,000
- 50,000
- 55,000
- 60,000
40 men can finish a work in 25 days. In how many days,12 men will finish the same work?
- 83.33 days
- 7.5
- 19.2
- 70
Simplify the ratio 0.35 : 0.65.
- 35 : 65
- 5 : 13
- 7 : 13
- 2 : 3
See Solution
Change values to whole numbers.
Convert any decimal numbers to integers by multiplying both sides by 102 = 100 to eliminate all, 2, decimal places.
We then have:
0.35 : 0.65 = 35 : 65
Try to reduce the ratio further with the greatest common factor (GCF).The GCF of 35 and 65 is 5
Divide both terms by the GCF, 5:
35 ÷ 5 = 7
65 ÷ 5 = 13The ratio 35 : 65 can be reduced to lowest terms by dividing both terms by the GCF = 5 :
35 : 65 = 7 : 13
Therefore the answer is = 7 : 13Simplifying ratio of decimal numbers
PPSC Labour Officer\Inspector paperOn Map 1/2 inch is equal to 12 km. Distance between two points is 5 2/3 (17/3) inch. Calculate the distance in kilometers.
- 204
- 68
- 408
- 136
See Solution
1/2 inch is equal to = 12 km
1 inch equals to = 12 + 12 = 24 km
Distance between two points = 5 2/3 = 17/3 = 5.66 inch
Distance between two points in kilometers = 5.66 × 24 = 136 km
PPSC Labour Officer\Inspector paper40 days food is available for certain number of mens. If 1/3 of them do not attend the mess, then food will last for how many days?
- 50
- 60
- 70
- 80
See Solution
For example there are 40 mens and each of them eat 1 bread.
Total breads for 1 day = 40
Total breads for 40 mens for 40 days = 40×40= 1600.
1/3 of mens who do not attend the mess= 40/3 = 13.33
The mens who will attend the mess = 40-13.33= 26.66
Food will be available for 26.66 men for = 1600 ÷ 26.66 = 60 days.
PPSC Labour Officer/Inspector paper.